If you're using a Hohmann transfer, sure. But IIRC a Bi-elliptic transfer will get you on a collision with the Sun for less delta-v than escaping the solar system. That's where you speed up to get high and slow then burn to cut your velocity when there. For ratios of oribital radii over 15 it's more always more efficient than the standard Hohmann transfer and since the ratio is very large in this case it works much better. But in this case you're just trying to get within the radius of the Sun and don't even need the third burn to slow down.
Just getting into the sun isnt enough. The sun's outer layers are not very dense. A blob of uranium might survive long enough to come out the other side, at least on the initial few orbits.
The earth is orbiting the sun at 30 kilometers per second. So if we launched something into space, since it started on earth, it would have that speed (similar-ish to throwing a ball from a moving car). So that object would now also be orbiting the sun at 30 km/s. We would need to slow it down that much in order to "fall" into the sun.
Once something was in earth orbit, it would only take about 12 km/s of delta v (change in velocity) to escape the solar system.
Although you could do it with about 17km/s if you put it into a Holman transfer orbit to Venus and used a low flyby and aerobrake maneuver of Venus and that puts you into a flyby of Mercury which changes the orbital plane such that the ellipse intersects the corona.
Sad note that also limits your launch window to once every 113 years as I recall from the last time I did the math :-(.
From a technical perspective you push into an elliptical orbit that intersects Venus, you do a slight aerobreak (skim the surface of the atmosphere) to dogleg toward a Mercury intercept, and then as you pass Mercury it tightens your ellipse still further and you head out, and come back and fly through the outer corona of the Sun (which is its hottest point). At which point you're in a degenerate orbit that will go out and come back through the Sun's corona until you've been completely consumed/burned up.
Why do you have to slow it to 0 to hit the sun? Can't you just cruise at whatever speed you're cruising and redirect it with thrusters towards the sun?
In space (and any frictionless medium), you can't "redirect" an existing velocity vector with thrusters. You can only add a velocity vector. This means that if your desired direction is perpendicular to your current direction, your current speed is no good to you at all. If you're heading due "north" at 10mph, and you want to be heading due "east" at 10mph instead, you have to 1) fully negate your "north" velocity, and 2) come up with 10mph of "east" velocity from scratch.
Now, the trajectory of an object in solar orbit is exactly at right angles to the direction it needs to go in to hit the sun. No part of this velocity is helpful for getting to the sun - in fact it actively prevents it! The only vector that takes you directly into the sun is one with no sideways component - if you imagine yourself falling right in, any sideways nudge will cause you to miss it by a hair and go flinging off into a highly elliptical orbit. If you just ignore this and just thrust directly at the sun, hoping to overpower everything by brute force, then like a ballerina pulling her arms in, the more you try to get close to the sun with your thrusters, the faster your orbit will go; the closer you manage to get, the further out you'll be flung when you inevitably miss.
All this ignores that the sun is not a point, but quite a large ball - you can get away with some small horizontal velocity. A highly elliptical orbit will still do what you want if its lowest point is below the surface.
Once you're in orbit (say around the sun), you have to cancel the orbital velocity to fall into the object you're orbiting around. If you point at the sun and accelerate 1 km/s directly at it, you're still moving 30 km/s "sideways". All you'd end up doing is making the orbit more elliptical-shaped.
At least that's how I see it, but I am far from being an authority on this topic.
Thanks, I actually have it installed, but never made it through all the tutorials. I'll probably give it another shot, would make it much easier to get an understanding of simple questions like this one.
I'm no rocket scientist but perhaps that would cause the object to shift from the Earth's kinda-circular orbit into a highly-elliptical orbit, its existing sideways velocity (relative to the sun) causing it to be flung past the sun at more of a straight line and hence way out into the solar system instead.
The escape velocity from the sun is 42.1 km/s, while the earth is orbiting at 29.78 km/s. The 29.78 km/s is 3 times closer to the escape velocity than to 0 km/s.
Well, there's "I want to match Mars' orbit around the Sun, so I can orbit the planet," and then there's "I want to intersect Mars' orbit just as the planet is passing through so I smack into its surface and leave a big crater."
The latter takes a lot less delta v, but it has its drawbacks. Leaving the solar system, you don't have to budget for that rendezvous.
The Earth is moving around the sun at ~30km/s. The escape velocity of the sun is ~42km/s. So if you start from Earth, it only takes 12km/s of change in velocity (called "delta-V" by rocket scientists / KSP players) to leave the solar system, but more than twice that (30km/s) to slow down enough to hit the sun.
Counterintuitively, this is far more expensive than launching it into said black hole, or just out of the Solar System all together.